PASS EFFICIENCY Team Cl G Att Cmp Int Pct. Yds TD Eff. ------------------------------------------------------------------ 1. Erik Ainge.......... UT JR 1 17 11 1 64.7 291 4 274.4 2. J. Russell.......... LS JR 1 17 13 0 76.5 253 3 259.7 Not complaining, because it doesn't matter. Just trying to figure this out. How does Ainge have a higher efficiency than Russell? Lower Completion %, threw an INT, but more TD's and Yrds. Anyone know the formula?

I found this: NCAA Pass-Efficiency Formula To determine a pass-efficiency rating, multiply a passer's yards per attempt by 8.4; add the number obtained by multiplying pass completions per attempt by 100; add the number obtained by multiplying touchdowns per attempt by 330; and subtract the number obtained by multiplying interceptions per attempt by 200. The formula is as follows: ER = TY/PA*8.4+PC/PA*100+TD/PA*330-I/PA*200, where TY=total yards; PC=pass completions; PA=pass attempts; TD=touchdowns; I=Interceptions; ER=Efficiency Rating.

Well, I did the math using this formula. JR came out to 257.09, Ainge came out to 316.52. Amazingly this formula only penalizes Ainge 10 points for the pick. Doesn't make much sense. Either that or my math sucks.